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How can we put the result that appear at console in a file

2 votes

this is y code

try {

File file = new File("/C:/Users/workspacememoire12/aaaaa/src/aaaaa/class.xml");
//File file1 = new File("/C:/Users/workspacememoire12/memoire/bin/memoire/class1.xml");
DocumentBuilder dBuilder = DocumentBuilderFactory.newInstance()
.newDocumentBuilder();

Document doc = dBuilder.parse(file);

System.out.println("Root element :" + doc.getDocumentElement().getNodeName());

if (doc.hasChildNodes()) {

printNote(doc.getChildNodes());

}

} catch (Exception e) {
System.out.println(e.getMessage());
}}
}

private static void printNote(NodeList nodeList) {

for (int count = 0; count < nodeList.getLength(); count++) {

Node tempNode = nodeList.item(count);

// make sure it's element node.
if (tempNode.getNodeType() == Node.ELEMENT_NODE) {

// get node name and value
System.out.println("\nNode Name =" + tempNode.getNodeName() + " [OPEN]");
System.out.println("Node Value =" + tempNode.getTextContent());

if (tempNode.hasAttributes()) {

// get attributes names and values
NamedNodeMap nodeMap = tempNode.getAttributes();

for (int i = 0; i < nodeMap.getLength(); i++) {

Node node = nodeMap.item(i);
System.out.println("attr name : " + node.getNodeName());
System.out.println("attr value : " + node.getNodeValue());

}

if (tempNode.hasChildNodes()) {

// loop again if has child nodes
printNote(tempNode.getChildNodes());

}

System.out.println("Node Name =" + tempNode.getNodeName() + " [CLOSE]");

try{

PrintWriter out = new PrintWriter(new FileWriter("ommmm.txt"));

out.println( ""+tempNode.getTextContent());
out.close();

PrintStream myconsole = new PrintStream(new File("C:/Users/workspacememoire12/aaaaa/src/class.txt"));
System.setOut(myconsole);
myconsole.print(" Node Name =" + tempNode.getNodeName() + " [CLOSE]");
myconsole.print( "\nNode Name =" + tempNode.getNodeName() + " [OPEN]");

}

catch(FileNotFoundException fx){
System.out.println(fx);} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}

}

this code shown the resut in the consol but a need it in File

نشر على 14:56, الأحد 8 ماي 2016 By Meiem Amirat (9 points)
In Bases de données avancées

أجوبة (2)

جواب (1)

-2 votes

public class NewMain1 {

    static FileWriter fw;
    public static void main(String argv[]) {

    try {

   File file = new File("d:/aaa.xml");

        fw = new FileWriter("d:/aaa1.xml");
   DocumentBuilder dBuilder = DocumentBuilderFactory.newInstance()
                             .newDocumentBuilder();

   Document doc = dBuilder.parse(file);

   //System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
        fw.write("Root element :" + doc.getDocumentElement().getNodeName());
   if (doc.hasChildNodes()) {

       printNote(doc.getChildNodes());

   }
        fw.flush();

    } catch (Exception e) {
   System.out.println(e.getMessage());
    }

}

private static void printNote(NodeList nodeList) throws IOException {

    for (int count = 0; count < nodeList.getLength(); count++) {

   Node tempNode = nodeList.item(count);

   // make sure it's element node.
   if (tempNode.getNodeType() == Node.ELEMENT_NODE) {

       // get node name and value
       //System.out.println("\nNode Name =" + tempNode.getNodeName() + " [OPEN]");
       //System.out.println("Node Value =" + tempNode.getTextContent());
                fw.write("\nNode Name =" + tempNode.getNodeName() + " [OPEN]");
       fw.write("Node Value =" + tempNode.getTextContent());

       if (tempNode.hasAttributes()) {

           // get attributes names and values
           NamedNodeMap nodeMap = tempNode.getAttributes();

           for (int i = 0; i < nodeMap.getLength(); i++) {

               Node node = nodeMap.item(i);
               //System.out.println("attr name : " + node.getNodeName());
               //System.out.println("attr value : " + node.getNodeValue());
                                fw.write("attr name : " + node.getNodeName());
               fw.write("attr value : " + node.getNodeValue());

           }

       }

       if (tempNode.hasChildNodes()) {

           // loop again if has child nodes
           printNote(tempNode.getChildNodes());

       }

       //System.out.println("Node Name =" + tempNode.getNodeName() + " [CLOSE]");
                fw.write("Node Name =" + tempNode.getNodeName() + " [CLOSE]");

   }

    }

}

}

نشر على 17:40, الجمعة 20 ماي 2016 by Mouadh Bekhouche (17 points)
In Bases de données avancées

جواب (2)

1 votes	jjust put those lines in the main File file2 = new File("C:\\Users\\ADMIN\\workspace\\MyProject\\file02.xml"); FileOutputStream fis = new FileOutputStream(file2); PrintStream out = new PrintStream(fis); System.setOut(out);
	نشر على 19:05, السبت 21 ماي 2016 by bendjebbqr hanane (2 points) In Bases de données avancées